EfficientWatt
Well-Known Member
It's a simple equation : Total Watts consumed by led = Par watts + Heat loss watts
SO IF:
- You know how much energy goes in (electricity consumed / Watts)
- You know how much light is emited (= electricty energy converted into light energy)
Then:
- The difference between both is the inefficiency part, ie direct heat.
SO IF:
- You know how much energy goes in (electricity consumed / Watts)
- You know how much light is emited (= electricty energy converted into light energy)
Then:
- The difference between both is the inefficiency part, ie direct heat.
thanks, I suppose that is a good answer for the real world. I was asking how you guys know 50% of the power put into a LED comes out as PAR watts. But maybe that math would be getting kind of crazy and I really don't need to know that.