RyanTheRhino
Well-Known Member
for the guy below:
The Jump from a 400watt hps to a 600watt will increase your grow rooms temps by 33%
becasue it transfers 33% more energy to the air per/sec
if your room is 80(f) with a 400w hps it will be 106(f) with a 600 watt hps
to find how much hotter any watt bulb is use this formula
(higher wattage) - (lower wattage) = diffrence in watts
(diffrence in watts) / (higher wattage)= %more watts
(Current temp X %more watts) +(Current temp) = (Temp with higher wattage)
the math below just proves that it is a linear trend
I came out with aprox... a 400 watt hps in a 16 square foot room will change the temp +.48294(F)/per hour
i understand that if i say that you would think the room heats up forever but it will stop because of ventilation.. i am only using these 2 points to figure out the % difference
so for a
400 watt = +.48294(f)/per hour
600 watt = +.72135(f)/ per houre
A 600 watt hps is 34% hotter
well i just lit up so im done with math... plus u would have to give me like 20 different data points to calculate the actual temp of your cab. so if you think your setup could handle a 34% increase in heat go for it....
if anyone is wondering how i did the math.
i started off with the watts (1 watt = 1 joule/sec) after that i have the energy to pluge into
q=mc(delta)T
q= energy = 400j/s
m= mass = 1.5g/per 16square foot room i had to use Pv=nrt to find that out
c= heat capacity of air= 1.012kj/kg
DeltaT= temp change and thats what i solved for
for the mass
pv=nrt
p = pressure= 1 atm
v= volume = 125 cubed meters
n= moles = solved to be = .052
r= constant.= 8.314
t= 25(C) room temp
mass = moles*atomic weight
atomic weight of air is 28.97g/mol
The Jump from a 400watt hps to a 600watt will increase your grow rooms temps by 33%
becasue it transfers 33% more energy to the air per/sec
if your room is 80(f) with a 400w hps it will be 106(f) with a 600 watt hps
to find how much hotter any watt bulb is use this formula
(higher wattage) - (lower wattage) = diffrence in watts
(diffrence in watts) / (higher wattage)= %more watts
(Current temp X %more watts) +(Current temp) = (Temp with higher wattage)
the math below just proves that it is a linear trend
I came out with aprox... a 400 watt hps in a 16 square foot room will change the temp +.48294(F)/per hour
i understand that if i say that you would think the room heats up forever but it will stop because of ventilation.. i am only using these 2 points to figure out the % difference
so for a
400 watt = +.48294(f)/per hour
600 watt = +.72135(f)/ per houre
A 600 watt hps is 34% hotter
well i just lit up so im done with math... plus u would have to give me like 20 different data points to calculate the actual temp of your cab. so if you think your setup could handle a 34% increase in heat go for it....
if anyone is wondering how i did the math.
i started off with the watts (1 watt = 1 joule/sec) after that i have the energy to pluge into
q=mc(delta)T
q= energy = 400j/s
m= mass = 1.5g/per 16square foot room i had to use Pv=nrt to find that out
c= heat capacity of air= 1.012kj/kg
DeltaT= temp change and thats what i solved for
for the mass
pv=nrt
p = pressure= 1 atm
v= volume = 125 cubed meters
n= moles = solved to be = .052
r= constant.= 8.314
t= 25(C) room temp
mass = moles*atomic weight
atomic weight of air is 28.97g/mol