If i is the sqr root of -1

Jolijn

Jolijn

Well-Known Member
when you take the square root of a square root, you're basically going to the power of .25 (because square root of anything is .5 power to)
 
stalebiscuit

stalebiscuit

Well-Known Member
i remember these questions fro pre-calc

it sucks hardcore, but count your lucky stars your not doing angle identities yet, then double anlge and half angle identities are the worst
 
Bookworm

Bookworm

Well-Known Member
stalebiscuit said:
i remember these questions fro pre-calc

it sucks hardcore, but count your lucky stars your not doing angle identities yet, then double anlge and half angle identities are the worst
Click to expand...
what the hell is an angle identity?

I've taken both AP calc classes (5s on both tests) and I'm almost done with my college calc, and I've never heard of angle identities.
 
stalebiscuit

stalebiscuit

Well-Known Member
Bookworm said:
what the hell is an angle identity?

I've taken both AP calc classes (5s on both tests) and I'm almost done with my college calc, and I've never heard of angle identities.
Click to expand...
google is the best way to explain this

Trigonometric Identities Equations - Trigonometry - EquationSheet

if you have done this then you know what it looks like, trust me (what year are you, im sure you have done it if youve been in college like a year er so, this shit is kinda basic or so they say)
 
Bookworm

Bookworm

Well-Known Member
stalebiscuit said:
google is the best way to explain this

Trigonometric Identities Equations - Trigonometry - EquationSheet

if you have done this then you know what it looks like, trust me (what year are you, im sure you have done it if youve been in college like a year er so, this shit is kinda basic or so they say)
Click to expand...
oh! that was back in the APs, I know what you mean. you just memorize em and move on with life. Now triple integrals with conversion to spherical cooridnates, that's a bitch.
 
stalebiscuit

stalebiscuit

Well-Known Member
Bookworm said:
oh! that was back in the APs, I know what you mean. you just memorize em and move on with life. Now triple integrals with conversion to spherical cooridnates, that's a bitch.
Click to expand...
hahaha, thats exactly why im not a math major, im going bio

i could tell you all day about an antiport and acetylcolene (spelling on that is off im sure) and all that jazz
 
hom36rown

hom36rown

Well-Known Member
the square root of i is +/-( (v/(2)/2) + (v/(2)/2)i ). the square root of that is
+/-( ((4^v/2)/(v/2))+((4^v/2)/(v/2)i )

v/ is supposed to be a radical sign in case you didnt catch that, and 4^v/ is root 4
 
Bookworm

Bookworm

Well-Known Member
hom36rown said:
the square root of i is +/-( (v/(2)/2) + (v/(2)/2)i ). the square root of that is
+/-( ((4^v/2)/(v/2))+((4^v/2)/(v/2)i )

v/ is supposed to be a radical sign in case you didnt catch that, and 4^v/ is root 4
Click to expand...
so

i^.5 = +{(2^.5)/2 + [(2^.5)/2]i}

and i^.25 = ???????
 
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