JohnnyStillwater
New Member
The frequency of a far red photon (750nm) is about half the frequency of a blue (400nm) photon and thus has about half the energy of a blue photon. Per watt electrical energy twice as much far red photons can be created assuming the far red LED and the blue LED are equally efficient.
Let's plug in some numbers:
E = h x f E=Energy in Joule, h = Planck's constant in kg m^2/s, f = Frequency in Hz
f = c / l f = Frequency in Hz, c = Speed of light in m/s, l = wavelength in m
Then E = h x c / l = 6.626 x 10^-34 x 0.3 x 10^9 /( 750 x 10^-9) = 2.66 x 10^-19 Joule.
That is the energy of a far red photon. The inverse (reciprocal) equals the number of far red photons we get using 1 Joule of electrical energy.
So: 0.376 x 10^19 photons
That is still an unfamiliar number... How many micro mols is that? One mol equals 6.0 x 10^23 units (Avogadro's number; molecules, ions, photons, whatever).
0.376 x 10^19 / (6.0 x 10^23) = 0.0627 x 10^-4 mol = 6.27 umol/Joule
Note that the PPFD of a far red grow lamp is zero because far red is not within the PAR range! The most efficient grow light commercially available seems to yield 2.9 umol/Joule.
Now the real world and my questions:
- Far red seems to benefit plant growth as much as photons in the PAR range but only in conjunction with PAR. Would a combination of red and far red work? If so, what is the minimum percentage of red photons needed?
- Green light penetrates the canopy more. How important is that?
- An overall whitish spectrum helps identifying problems with the plants. Can I just turn on some normal white light to check for problems but let the plants grow in red light?
- Blue light seems to help making the plants more dense and sturdy in the vegetative phase. What percentage of blue to other photons is needed? Is there a need for blue in the bloom phase?
- Is some ultra violet important?
- How efficient are LEDs anyway?
- What percentage of energy is lost by the drivers?
- What do you think of the idea to push the spectrum as much as possible towards the far red in order to be energy efficient?
Let's plug in some numbers:
E = h x f E=Energy in Joule, h = Planck's constant in kg m^2/s, f = Frequency in Hz
f = c / l f = Frequency in Hz, c = Speed of light in m/s, l = wavelength in m
Then E = h x c / l = 6.626 x 10^-34 x 0.3 x 10^9 /( 750 x 10^-9) = 2.66 x 10^-19 Joule.
That is the energy of a far red photon. The inverse (reciprocal) equals the number of far red photons we get using 1 Joule of electrical energy.
So: 0.376 x 10^19 photons
That is still an unfamiliar number... How many micro mols is that? One mol equals 6.0 x 10^23 units (Avogadro's number; molecules, ions, photons, whatever).
0.376 x 10^19 / (6.0 x 10^23) = 0.0627 x 10^-4 mol = 6.27 umol/Joule
Note that the PPFD of a far red grow lamp is zero because far red is not within the PAR range! The most efficient grow light commercially available seems to yield 2.9 umol/Joule.
Now the real world and my questions:
- Far red seems to benefit plant growth as much as photons in the PAR range but only in conjunction with PAR. Would a combination of red and far red work? If so, what is the minimum percentage of red photons needed?
- Green light penetrates the canopy more. How important is that?
- An overall whitish spectrum helps identifying problems with the plants. Can I just turn on some normal white light to check for problems but let the plants grow in red light?
- Blue light seems to help making the plants more dense and sturdy in the vegetative phase. What percentage of blue to other photons is needed? Is there a need for blue in the bloom phase?
- Is some ultra violet important?
- How efficient are LEDs anyway?
- What percentage of energy is lost by the drivers?
- What do you think of the idea to push the spectrum as much as possible towards the far red in order to be energy efficient?