how do you know they will work with the drivers?You could also use the vero 29 orthe cxa 3070 for a boost in power ddisplacement and efficiency. But it will be more expensive.
how do you know they will work with the drivers?
so is it safe to hook up 2 veto 18s to each?Vero 18 or anything with similar V-A characteristic is probably the best for that supply.
The remaining voltage could be dropped using monos at 650mA in series if you wanted.
so is it safe to hook up 2 veto 18s to each?
how would i calculate the total watts being put out from the lights? would it be 180watts in total?If you put an XP-E in series with each vero 18, it'd be safe, yes.
how would i calculate the total watts being put out from the lights? would it be 180watts in total?
Huh? I get the first line of math but the rest leaves me scratching my head. Care to share some brotherly insight Churchy?29V * 0.65A = 18.85W
For per channel so 113.1W electric dissipation for 6.
At 38% efficient, 43W of radiant power is put out from the lights.
The efficiency though... still trying to decode the mysterious algorithm you used.
Right. Ok. Let me now clear my english for you to understand. The 38% variable. How come?I used the mysterious power of multiplication.
0.38 * 113W = ~43W
Right. Ok. Let me now clear my english for you to understand. The 38% variable. How come?
Right, but why not 100% or 420%? Why choose 38% arbitrarily? Obviously your withholding some information that you feel fit to introduce but not fully explain, something like that of your math."At 38% efficient, 43W of radiant power is put out from the lights."
38% is a given because i said "at 38%".
I would like to think you have more widespread knowledge and maybe even experience over these matters but I could be kidding myself. Only your participation, which has been gradually picking up, and demonstrations will overcome my doubt.I have a feeilng the efficiency of your every day vero 18 3500k 80cri at 650mA is closer to 38% than 100% or 420%... lets just call it a hunch that efficiency is not 100% or 420% if you catch my drift. Then you'd be breaking the laws (of thermo).
If your efficiency is 39%, plug in 39%.
I sort of catch your drift but not entirely. So you are saying that, in short, even though a given Bridgelux Vero 18 may show ~30W actual on a meter, that, which matters most, the radiancy of the light, meaning the spectra of UVC to Infrared, may only be ~%40 while being ran at ~650mA, while the rest is quite possibly heat or some other form of energy? Or is this not the case?
Do you believe the efficiency variable, 0-100%, varies due to the current that is discharged from the driver or do you think it's based off the materials used to build the light/COB/star and how well it was constructed?Yes, exactly. If the light is 40% efficient and it takes 100W of electric power, it will give off 40W of radiant power and 60W of direct heat..