Growmau5
Well-Known Member
Hey growers,
I am in the market for a new mini split a/c unit, and I really want to pair it properly with my lights. I am specifically looking at the Fujitsu rls3 family of units. Their 9000 btu is the most efficient highest SEER rating in the world right now. Efficiency is very important to me, but sadly the 9000 btu is not going to be enough. To my understanding, with all mini splits as you increase the cooling power in BTUs you begin to drop in SEER incrementally. So bigger is not always better, and for this application, I really want this thing to be appropriately sized to bank the kwh savings.
As a base line, I would like to know what the approximate BTU output of a (3) cxa3070 AD bin on a HLG185h-c1400 is. Then I can simply multiply this by how ever many bars of this combination I have.
I came across this article and it threw a wrench in my understanding of LED efficiency.
http://www.etcconnect.com/Support/Articles/How-To-Quickly-Calculate-BTUs-Emitted-from-a-Source-Four-For-HVAC-Purposes.aspx
Calculating Heat Load from Lighting Fixtures
Whenever doing heat-load calculations, we must always count 100% of the fixture wattage-any fixture's wattage-as heat, regardless of efficiencies at the source. In any enclosed space, virtually all of the light produced by a lighting fixture is eventually absorbed by surrounding materials (walls, ceilings, etc.). When light gets absorbed by these materials, photons are converted into heat.
New lighting technologies, such as LEDs, allow luminaires to produce light more efficiently, or with higher efficacy than incandescent lamps. This means that we get more lumens per watt; however, heat per watt is constant. What matters is that fewer watts are used to produce comparable brightness, not that these fixtures somehow produce less heat for the wattage that they consume.
1 watt of electricity used by a luminaire = 3.4128 BTUs per hour
The same math works for any lighting fixture.
For average industrial heat-pump or electric air-conditioner types of HVAC equipment, it takes approximately 0.4 watts of cooling power to offset each 1 watt of power consumed by a light source. Smaller-scale HVAC systems might require more power than this, and certain specialized systems (such as evaporative coolers) may use somewhat less, but this is a useful generalization for most applications.
If anyone can clear this up or provide me with a BTU calculation of the example posted above, it would be much appreciated.
I am in the market for a new mini split a/c unit, and I really want to pair it properly with my lights. I am specifically looking at the Fujitsu rls3 family of units. Their 9000 btu is the most efficient highest SEER rating in the world right now. Efficiency is very important to me, but sadly the 9000 btu is not going to be enough. To my understanding, with all mini splits as you increase the cooling power in BTUs you begin to drop in SEER incrementally. So bigger is not always better, and for this application, I really want this thing to be appropriately sized to bank the kwh savings.
As a base line, I would like to know what the approximate BTU output of a (3) cxa3070 AD bin on a HLG185h-c1400 is. Then I can simply multiply this by how ever many bars of this combination I have.
I came across this article and it threw a wrench in my understanding of LED efficiency.
http://www.etcconnect.com/Support/Articles/How-To-Quickly-Calculate-BTUs-Emitted-from-a-Source-Four-For-HVAC-Purposes.aspx
Calculating Heat Load from Lighting Fixtures
Whenever doing heat-load calculations, we must always count 100% of the fixture wattage-any fixture's wattage-as heat, regardless of efficiencies at the source. In any enclosed space, virtually all of the light produced by a lighting fixture is eventually absorbed by surrounding materials (walls, ceilings, etc.). When light gets absorbed by these materials, photons are converted into heat.
New lighting technologies, such as LEDs, allow luminaires to produce light more efficiently, or with higher efficacy than incandescent lamps. This means that we get more lumens per watt; however, heat per watt is constant. What matters is that fewer watts are used to produce comparable brightness, not that these fixtures somehow produce less heat for the wattage that they consume.
1 watt of electricity used by a luminaire = 3.4128 BTUs per hour
The same math works for any lighting fixture.
For average industrial heat-pump or electric air-conditioner types of HVAC equipment, it takes approximately 0.4 watts of cooling power to offset each 1 watt of power consumed by a light source. Smaller-scale HVAC systems might require more power than this, and certain specialized systems (such as evaporative coolers) may use somewhat less, but this is a useful generalization for most applications.
If anyone can clear this up or provide me with a BTU calculation of the example posted above, it would be much appreciated.
today and maybe my math are wrong...sorry... and its only my inexpert pov too...
