AquariusPanta
Well-Known Member
Let's figure this one out:My lamp is approx 240 par watt ( 4 x 3490 & 4 x v29)
My space is 50" x 24" = 1200"sq
1200"sq =8.3'sq.
240 par W / 8.3'sq. = 28.8 par W sq ft
28.8 x 45 = 1296ppfd If this is correct I would likely benefit from a further increase in the clearance.
Is the metric conversion accounted for by the 4.5 vs 4.7 conversion factor?
1.) PAR W = ~240W
2.) Targeted Area = [(50" x 1' / 12")*(24" x 1' /12")] = ~8.33 square feet = 0.774 square meters
3.) PPF = [(240 PAR W) * (4.70 umol/J) = 1128 umol
^^^^ the 4.70 was arbitrary, as I don't know which temperatures you're running with your Vero 29s and CXB3590s
4.) PPFD = PPF / Targeted Space = 1128 umol / 0.774 square meters = ~1458 PPFD (gross, not net)
Conclusion: A great PPFD number to have for flowering, depending on distance between light sources and plants.