Airwalker16
Well-Known Member
Really? The numbers and values on top don’t neeed to be the same. And I’d clip the 5th terminal?
Having an issue with my chiller not turning off.
- Thread starter Airwalker16
- Start date
dstroy
Well-Known Member
They are the same 250vac 10a 50-60hz
Yes, you would cut the pin to match the one you desolder.
Airwalker16
Well-Known Member
So does the 50hz cos.01 mean the pin that’s cut off? N-O is the 10a-250v and then 10a120v 10a 24v?
Airwalker16
Well-Known Member
SO the 125 & 28V are fine because they’re here higher than 120 & 24?
dstroy
Well-Known Member
The coil is 12vdc, and the contacts are rated for up to 250vac 10a 50-60hz. It is a direct replacement, different manufacturer.
It’s super simple to replace, just desolder the old one, cut the pin on the new one to match the old one and then solder the new one on.
Airwalker16
Well-Known Member
OK can you determine which relay it is?
dstroy
Well-Known Member
You can find out which relay it is. Follow the trace on the pcb back from the wire that goes to the compressor/fan. Whichever relay that trace goes to is the one to replace.
Airwalker16
Well-Known Member
And just use solder wick?
dstroy
Well-Known Member
Yes.
When you are done it is very important that the trace with the extra solder on it still has extra solder on it. The reason it is there is to increase the current capacity of the trace and it is necessary in this application.
Airwalker16
Well-Known Member
So if RED is Cool the its the relay nearest the thermistor connection?
you'll need a straight on pic for the traces to know huh...
Airwalker16
Well-Known Member
Amazon’s railing me in shipping so I think I’ll use eBay. Would this work just the same?
https://www.ebay.com/itm/2pcs-HRS4H...513934?hash=item2a7fb9de4e:g:IhUAAOSwTM5Y8j9k
@dstroy
https://www.ebay.com/itm/2pcs-HRS4H...513934?hash=item2a7fb9de4e:g:IhUAAOSwTM5Y8j9k
@dstroy
dstroy
Well-Known Member
Yes those will work
Airwalker16
Well-Known Member
Omg thank you so much dstroy.... I’m so so SO happy I figured it out.
Jypsy Dog
Well-Known Member
Airwalker16
Well-Known Member
Nice google image search there.
Airwalker16
Well-Known Member
Airwalker16
Well-Known Member
@dstroy I have a question for you. I understand how this relay circuitry works a little bit better now. But my question is where the solder joint that is very thick is connected to both commons on the relays, when power is applied to them and the coil is energized to pull the normally open arms to closed, how does each relay get turned on independently when the commons are connected?
dstroy
Well-Known Member
You just asked why a switch is a switch. Because it does what it is.
They share a common “supply”, which is AC mains voltage and what is being “switched”, not the 12vdc that actuates the relay. The 12vdc is probably stepped down by that regulator to 5vdc or 3.3vdc which goes to the micro controller and the micro controller has a separate output pin for each circuit it controls. In this case there are two output pins that control relays. All of the stuff that runs on DC voltage shares a common ground, which is not the same as an AC “ground”.
Airwalker16
Well-Known Member
HydroRed
Well-Known Member
You can see where the contact is burnt. Glad you got it worked out, and it likely cost all of about what $4 for the relay lol
