Fentanyl conversion

MrEDuck

MrEDuck

Well-Known Member
A mole is 6.022 * 10^23 molecules, which will have a mass in grams equal to the compounds molecular weight. Molecular weights are easily obtained by looking them up. The liter of solvent is probably what the NPP would be dissolved in prior to the reaction with aniline.
 
racerboy71

racerboy71

bud bootlegger
hey mre, i had always thought a mole was 6.022 x 10 to the -23 power, am i wrong about this?? it's like the one formula i remembered from chem class in jr year..
oh, that and the speed of sound at sea level..
 
MrEDuck

MrEDuck

Well-Known Member
Nope, if it was ten to the -23 you'd end up with a tiny fraction of a particle. Still you almost had it right, at least you remembered something from chem class.
 
AndrewDeeKing

AndrewDeeKing

Active Member
And a MMOL is a MOL divided by 1000...correct?

10 mmole of NPP is dissolved in a minimal volume of aniline (about 5-6 ml)

What is 10 MMOL of N-Phenyl-Imine??? (the NPP) I looked up the molecular weight but can not fine. So how much would I add to the 6 ml of Aniline?


ALSO! Clear out your inbox so I can message you :P
 
racerboy71

racerboy71

bud bootlegger
MrEDuck said:
Nope, if it was ten to the -23 you'd end up with a tiny fraction of a particle. Still you almost had it right, at least you remembered something from chem class.
Click to expand...
yeah, i wasn't a real big fan of chemistry.. i was a science geek in high school, but always hated math class, and to me chem was way more of a math then a science...
 
MrEDuck

MrEDuck

Well-Known Member
The imine is the condensation product of the NPP and analine. Condensation is the loss of a water molecule so the product will have a molecular weight equal to the molecular weight of the reactants minus 18 (the MW of water). There's room in my inbox, I cleared some the other day.
 
You must log in or register to reply here.
Top