quick question about amps x volts =watts

mrLifted

Member
so i found this formula

amps x volts = watts

amps x 120 = 600----- 600/120 = 5 amps
amps x 240 = 600 ---- 600/240 = 2.5 amps

i was wondering if this correct?


and if it is, does that mean if i run power on a 240v i use less amps?


how does that work?... i would really like a simple explanation. please and thanks
 

mustang519

Well-Known Member
correct you use 1/2 the amps with twice the voltage------ but the consumption of power is equal ---- the power bill will not go down----sigh
 

Sand4x105

Well-Known Member
so i found this formula

amps x volts = watts

amps x 120 = 600----- 600/120 = 5 amps

amps x 240 = 600 ---- 600/240 = 2.5 amps



i was wondering if this correct?





and if it is, does that mean if i run power on a 240v i use less amps?





how does that work?... i would really like a simple explanation. please and thanks




GUESS AGAIN….


You have two legs of hot both carrying power, so add 2 X 2.5 = same 5 amps...

The only advantage to running 220 vac is you can run smaller wire to the unit [which if you look/inside fixture], all the wires will be like 18 awg…


Ohms Law is what you posted above, let it be your friend….
 

Sand4x105

Well-Known Member
120 vac has one leg of hot, plus one leg of neutral/ground between them = 120 vac

240 vac has two legs of hot both/either leg to ground is 120 vac

Between the two hot legs of 240 vac is 240 volts, with either leg to ground still 120 vac

Half of your current is run on ½ the 240 [120] and half on the other half…

Get it?
 

mrLifted

Member
120 vac has one leg of hot, plus one leg of neutral/ground between them = 120 vac

240 vac has two legs of hot both/either leg to ground is 120 vac

Between the two hot legs of 240 vac is 240 volts, with either leg to ground still 120 vac

Half of your current is run on ½ the 240 [120] and half on the other half…

Get it?
No buddy i dont sorry. im kinda lost.
ps what do you reffer to when you say 120 vac?
 

Stevie51

Active Member
First you must understand how a residential 240/120 volts circuit breaker panel is wired, and more importantly how to balance the load on the 120 volts branch circuits, so that for every 120 volts load on a branch circuit using hot wire L1 to neutral, you should try to place an equal 120 volts load on a separate branch circuit using hot wire L2 to neutral. Because a 240 volts branch circuit use no neutral, the current flowing through hot wire L1 and hot wire L2 is always equal under a 240 volts load. You are aware that a 240 volts circuit use a double pole circuit breaker connected to L1 on one half of the breaker and L2 on the other half of the breaker. While its true that the current flowing in each individual ballast power cord is only half the amount of amps on 240 volts, lets look at an example of using even numbers (2,4,6,8, ect.) of ballasts of the same wattage. Using your example of four 600 watts @ 240 volts, 2.5 + 2.5 + 2.5 + 2.5 amps equal a total of 10 amps flowing on hot wire L1 and hot wire L2. Using four 600 watts @ 120 volts, with two 600 watts loads placed across hot wire L1 and neutral on one branch circuit and two 600 watts loads placed across hot wire L2 and neutral on a separate branch circuit, 5 + 5 amps equal a total of 10 amps flowing on hot wire L1, and 5 +5 amps equal a total of 10 amps flowing on hot wire L2.
 

Stevie51

Active Member
so i found this formula

amps x volts = watts

amps x 120 = 600----- 600/120 = 5 amps
amps x 240 = 600 ---- 600/240 = 2.5 amps

i was wondering if this correct?


and if it is, does that mean if i run power on a 240v i use less amps?


how does that work?... i would really like a simple explanation. please and thanks
You are ignoring an important part of Ohms Law...the resistance of the load (ballast). In order to maintain the exact same wattage, the impedance (resistance) of the ballast had to be increase four times the amount of resistance (ohms) when the input voltage was double (from 120 volts to 240 volts). Had the resistance not been changed inside the ballast, the current (amps) through the ballast would have doubled when the input voltage was double from 120 volts to 240 volts and thus would have increased the wattage from 600 watts to 2400 watts before going up in smoke.
 
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