Exactly what I was asking for thank you!
So do you suggest just using the same Vero 3000k lights the entire seed - > harvest grow? I would still shoot for ~35w/sqft right (flower)?
In your situation, I'd advise either 700mA or 1050mA. You get 40% efficiency with the V18 @ 700mA, while with 1050mA you gain a little more light and heat, while lowering the efficiency close to 38%.
Exactly what I was asking for thank you!
So do you suggest just using the same Vero 3000k lights the entire seed - > harvest grow? I would still shoot for ~35w/sqft right (flower)?
You could certainly grow a 'weed' from start to finish with either 2700K or 5000K. The results will vary though, some more desirable than others.
The 3000K seems to be a popular choice for seed-to-harvest but things change over time so again, results may vary with newer products. If your feeling chancy, roll with the 3500K on the Vero side.
Someone asked what my final yield was . I will go post it in the other thread too. But...
2x4 tent.
500w
268grams
about 1/2g per watt.
It should be noted that I was beyond the point of diminishing returns as far as w per sq ft. I have put these same three bars in a 4x4 tent now. (twice the space) and will see if I can double my yield number with the same amount of photon.
I'm assuming that the one-half gram per watt is based off of the total draw (watts) from each cob and then added together and divided by dry weight. The only problem that I have with this methodology ($/W or Grams/W) is that the formula takes into account wattage of both PAR and heat. So technically and more reasonably, if one your COBs is producing 50W off the killa-watt meter and is running 33% efficient, than only 16.5W of PAR are being transferred and consumed. This being said, 10x COBs (all giving 16.5W PAR each) gives you 165W PAR output, raising your ratio of grams over watts to 1.6 grams per PAR watt.
Some people are most likely going to get grumpy and throw a hissy fit at this point in the discourse because most are accustomed to old ways of thinking but the former method undermines the purpose of solving for PAR/heat efficiencies. Heat doesn't grow buds, PAR does.