COB Manufacturers other than CREE or BRIDGELUX

Which led brand /manufacturer do you use ?

  • cree

    Votes: 98 58.0%
  • bridgelux

    Votes: 48 28.4%
  • sharp

    Votes: 1 0.6%
  • osram

    Votes: 4 2.4%
  • nichia

    Votes: 9 5.3%
  • toyonia

    Votes: 0 0.0%
  • citizen

    Votes: 32 18.9%

  • Total voters
    169

Corso312

Well-Known Member
@ttystikk - I am looking at both penetration and total build cost and how quickly I can put together. If I can take a 250w COB and run them @ 125w to get around 50% efficient, with 4 COBs I can build a 500 watt light. Much simpler than wiring up 20 COB@ 25w or 10 at 50w. I will build you a 700 watt light for $900, how does that sound. I have one if you want.:bigjoint:





That makes a lot of sense, Do you see an advantage to using one extremely large driver as opposed to multiple small drivers?
 

Hampsteri

Well-Known Member
If i can build 1035W cob and get 44% efficiency just under 800 euros i think its worth to try. Its not a big deal after that to add couple more if i need more spread to get yields.
 

welight

Well-Known Member
You do also sell heatsinks. :eyesmoke:

Those prices are competitive with anyone stateside on octopart assuming the shipping is comparable (and the drivers are as nice as mw). Would love to see the DS for those drivers.

How much would you charge (if you offered it) for a led engine with a cxb3590 "cd" on a mechatronix lsb9980-b? With or without reflectors?

Why aren't you building engines with 3070/3590?
LSB9980 only good to 30 watts
You do also sell heatsinks. :eyesmoke:

Those prices are competitive with anyone stateside on octopart assuming the shipping is comparable (and the drivers are as nice as mw). Would love to see the DS for those drivers.

How much would you charge (if you offered it) for a led engine with a cxb3590 "cd" on a mechatronix lsb9980-b? With or without reflectors?

Why aren't you building engines with 3070/3590?
lsb9980-b is only good to about 30 watts, is that doable for you?
Cheers
Mark
 

nevergoodenuf

Well-Known Member
@Corso312 If you have a small grow, it isn't that bad having a lot of smaller drivers, but the bigger your grow is the more of a head ache smaller drivers would be. I just started flowering with 2 of the Luna 300s 20" apart @ 330 watts each over a 4'x 5' area. Started the light at 32" and had to raise it 40" until they get use to it. Very happy so far, but will also be testing one at 250 watts per COB.
 

ttystikk

Well-Known Member
That makes a lot of sense, Do you see an advantage to using one extremely large driver as opposed to multiple small drivers?
I see an advantage in using more drivers in wieldy numbers; I had twenty five modules or light fixtures made, each with four CXB3590 driven at fifty watts on its driver. This gives me infinite options for altering spacing, intensity, grow style, etc. This kind of modularity in design is something I've practiced with some obssessiveness over the years and it continually pays off.
 

nevergoodenuf

Well-Known Member
All my light fixtures take 2 drivers and when I get the CLU55 it will require 4. 2 per COB. I bought the hlg 120 1050Bs but am still waiting for the CLU. All my light are remote drivers, and will eventually be in the attic, with a dimming panel in the room.
 

PurpleBuz

Well-Known Member
I see an advantage in using more drivers in wieldy numbers; I had twenty five modules or light fixtures made, each with four CXB3590 driven at fifty watts on its driver. This gives me infinite options for altering spacing, intensity, grow style, etc. This kind of modularity in design is something I've practiced with some obssessiveness over the years and it continually pays off.
pics ?
 

kmog33

Well-Known Member
Hi Guys
Can do spectral testing here, but would like someone other than me to do both Spectral and efficiency to provide independence on the results
Cheers
Mark
I would also be up for testing if you need any testers.


Sent from my iPhone using Tapatalk
 

nogod_

Well-Known Member
A little confused by the numbers. Is that 30w heat? Doesn't really make sense as anything else but wouldn't that mean you could run up to a 60w cob on there @ 50% efficiency?

LSB9980 only good to 30 watts

lsb9980-b is only good to about 30 watts, is that doable for you?
Cheers
Mark
 

welight

Well-Known Member
30 watts on LSB9980 is Pd(Power dissipation), so its can dissipate 30 watts of heat, if you run a CXB3590 at 30 watts, then yes it would work. But need to clarify efficiency or efficacy translates to running cost or value but whatever your running, watts is watts and must be dissipated. The best likely Mechatronix solution will be Moduled Xtra 9980, this can dissipate 48.9 watts, which coincidentally is what CXB3590 will be at 1400ma
Cheers
Mark
 

nogod_

Well-Known Member
My understanding is that a heatsink need only dispose of waste heat generated by the cob (the portion of energy not emitted as photons). So @49w the cob is only radiating something like 23w of heat.

That's why I asked because if they are rated for a 49w cob wouldn't they be assuming the efficiency of your emitter and basing the rating on that assumed value?

If I am running my cobs at 25w I'm only generating something like 10w of heat.

Sorry for all the Q's in the wrong spot, just want to get to the bottom of this as I am unfamiliar with surface reqs for radial heatsinks.

30 watts on LSB9980 is Pd(Power dissipation), so its can dissipate 30 watts of heat, if you run a CXB3590 at 30 watts, then yes it would work. But need to clarify efficiency or efficacy translates to running cost or value but whatever your running, watts is watts and must be dissipated. The best likely Mechatronix solution will be Moduled Xtra 9980, this can dissipate 48.9 watts, which coincidentally is what CXB3590 will be at 1400ma
Cheers
Mark
 

bassman999

Well-Known Member
My understanding is that a heatsink need only dispose of waste heat generated by the cob (the portion of energy not emitted as photons). So @49w the cob is only radiating something like 23w of heat.

That's why I asked because if they are rated for a 49w cob wouldn't they be assuming the efficiency of your emitter and basing the rating on that assumed value?

If I am running my cobs at 25w I'm only generating something like 10w of heat.

Sorry for all the Q's in the wrong spot, just want to get to the bottom of this as I am unfamiliar with surface reqs for radial heatsinks.
I was under the same undrstanding
 

welight

Well-Known Member
My understanding is that a heatsink need only dispose of waste heat generated by the cob (the portion of energy not emitted as photons). So @49w the cob is only radiating something like 23w of heat.

That's why I asked because if they are rated for a 49w cob wouldn't they be assuming the efficiency of your emitter and basing the rating on that assumed value?

If I am running my cobs at 25w I'm only generating something like 10w of heat.

Sorry for all the Q's in the wrong spot, just want to get to the bottom of this as I am unfamiliar with surface reqs for radial heatsinks.
No your correct, I was only considering led efficacy. With heatsinks I discount electrical efficiency, anecdotally I prefer to over engineer coolers. Placing a $40 COB on a $10 heatsink at the margins is a sleepless night.

If we consider LSB9980 in this context the math is, if=1400ma, vf=34.89, so watts =48.9W. Elect Eff =51%, so Pd becomes 23.47 watts. Lets assume case temp of 85C, probably higher than you would use and an ambient of 40C, I assume your rooms get warm, so case temp-Ambient is a delta of 45C. So our Rth is 45C/23.47watts=1.917C/w. We then need to deduct thermal resistance of TIM 1.19c/w-1c/w=0.65 Thermal resistance(I assume 1c/w for TIM but you may have better numbers on your material).
So based on this the LSB9980 would work. Please advise if I missed anything here
off course the best way to tell will be to test one so I will do that and advise results
Cheers
Mark
 
Last edited:

Abiqua

Well-Known Member
No your correct, I was only considering led efficacy. With heatsinks I discount electrical efficiency, anecdotally I prefer to over engineer coolers. Placing a $40 COB on a $10 heatsink at the margins is a sleepless night.

If we consider LSB9980 in this context the math is, if=1400ma, vf=34.89, so watts =48.9W. Elect Eff =51%, so Pd becomes 23.47 watts. Lets assume case temp of 85C, probably higher than you would use and an ambient of 40C, I assume your rooms get warm, so case temp-Ambient is a delta of 45C. So our Rth is 45C/23.47watts=1.917C/w. We then need to deduct thermal resistance of TIM 1.19c/w-1c/w=0.65 Thermal resistance(I assume 1c/w for TIM but you may have better numbers on your material).
So based on this the LSB9980 would work. Please advise if I missed anything here
off course the best way to tell will be to test one so I will do that and advise results
Cheers
Mark
I know many don't calculate their heatsinks thru pure resistance, but should we be adding 25%? to the heatsink resistance to account for point source to spread?

:peace:
 
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