you're group velocity is wrong^^
TROLL! KNOW ITZ KNOT!
ω=2πf (angular freq), k=2π/λ (wave#)
ω/k=λf=V[SUB]p or [/SUB]ω=kVp
dω/dk = Vp + k*dVp/dk
E=hf , or f=E/h, so Vp=λf=λE/h=E/p since DeBroglie says λ=h/p
E[SUP]2[/SUP]= (pc)[SUP]2[/SUP]+(mc[SUP]2[/SUP])[SUP]2[/SUP] , so V[SUB]p[/SUB]=c(1+(mc/ħk)[SUP]2[/SUP])[SUP]1/2[/SUP] ,where p=ħk
if V[SUB]g[/SUB]=dω/dk, then you'll find c[SUP]2[/SUP]/V[SUB]p[/SUB] as the result... which is kind of beautiful in its final simplicity.
Are you telling me that's wrong?
remember to put it out after a couple hits, dank dank like that is one hitter.
I gave it to my cat. And then put her in a box. Is she alive or dead?
How much you pay for that bowlpack?
I put that much in one bong rip...
It was a FREE promo pack. Although, I heard Raggy was trying to peddle them as nickel-bags to people high on codeine.
Heckler, what kind of stress techniques did you do to produce such a copious yield?
Thorium and Bragg Diffraction with X-rays...and ionized Ostrich Milk, the secret of Master Jamaican growers.
No delay.
