Does this answer a question? If so...how about translating into layman's terms?Look up phytochromes. (Pfr and Pr)
Pr aborbs a photon and becomes Pfr
Pfr absorbs a photon and it becomes Pr
Total amount of Pr + Pfr stays the same.
%Pfr = Pfr / (Pr+Pfr)
View attachment 2979676
If you use 660nm monochromatic light, you will cause Pr to convert to Pfr, the active form of phytochrome. Darkness will slowly cause Pfr to revert back to Pr. 730nm light will instantly convert all Pfr to Pr (%Pfr = 0), the inactive form (sleep).
Think of it like color vision, but with 2 cones. It allows the plant to see a gradient of color quality which it measures as %Pfr. At 500nm, Pr and Pfr absorb about the same so the equilibrium will cause %Pfr to change to about 50%.
The max %Pfr can theoretically go is about 85%, at 660nm because Pfr also absorbs at 660nm so the equilibrium works out to be about 85% there.
Does this answer a question? If so ... how about translating into layman's terms?Look up phytochromes. (Pfr and Pr)
Pr aborbs a photon and becomes Pfr
Pfr absorbs a photon and it becomes Pr
Total amount of Pr + Pfr stays the same.
%Pfr = Pfr / (Pr+Pfr)
View attachment 2979676
If you use 660nm monochromatic light, you will cause Pr to convert to Pfr, the active form of phytochrome. Darkness will slowly cause Pfr to revert back to Pr. 730nm light will instantly convert all Pfr to Pr (%Pfr = 0), the inactive form (sleep).
Think of it like color vision, but with 2 cones. It allows the plant to see a gradient of color quality which it measures as %Pfr. At 500nm, Pr and Pfr absorb about the same so the equilibrium will cause %Pfr to change to about 50%.
The max %Pfr can theoretically go is about 85%, at 660nm because Pfr also absorbs at 660nm so the equilibrium works out to be about 85% there.
. how about translating into layman's terms?