born2killspam
Well-Known Member
That will work, but will take a long time regardless of setup since it just can't pump alot of current..
If you have a multimeter, measure R between the electrodes and use V=IR and a resistorto create ~1V drop across the electrodes..
eg: Say your electrodes are separated by a 100ohm resistance.. With no resistor, I = 24V/100ohm = 0.24A.. But you'd be dropping all 24V across those electrodes, and allowing those junk reactions.. But with a 2.2kohm resistor in series, the new current would only be I=24V/2300ohm=0.01A, but the voltage dropped across the electrodes themselves would be V=0.01A*100ohm=1V, which disallows those higher energy reactions at the cost of reduced current.. Faraday explained how much current it takes to liberate a mole of atoms if you're interested..
If you have a multimeter, measure R between the electrodes and use V=IR and a resistorto create ~1V drop across the electrodes..
eg: Say your electrodes are separated by a 100ohm resistance.. With no resistor, I = 24V/100ohm = 0.24A.. But you'd be dropping all 24V across those electrodes, and allowing those junk reactions.. But with a 2.2kohm resistor in series, the new current would only be I=24V/2300ohm=0.01A, but the voltage dropped across the electrodes themselves would be V=0.01A*100ohm=1V, which disallows those higher energy reactions at the cost of reduced current.. Faraday explained how much current it takes to liberate a mole of atoms if you're interested..