is this the right way to calculate your nutrient mix?

okay, for example

micro is 5-0-1
bloom's 0-5-4

if you put 1ml micro 2 ml bloom, would that gallon be 5-10-9?

trying to keep track of a few things and curious if this is actually how it works

Yes sir it would be.

It's not quite that simple.
5-0-1 is NPK in per cent, but P is calc'd as P2O5 and K as K2O, ... so actual P and K are 43.6% and 83% of the quoted values.

1% K2O is actually 0.83% K. 1 ml in 1 gallon (call it 3800 ml) will yield 2.18 ppm K.
cn

hmm, going to have to examine that

43.6%* P
83%* k

would come out to the actual?

what is the actual for N?

sorry but can someone break this down a little for me? i just dont quite understand the whole concept

plast00 said:

sorry but can someone break this down a little for me? i just dont quite understand the whole concept

Click to expand...

Me to i still dnt understand

You need the conversion factors to convert the numbers on dilution:
% P2O5 to ppm P
% K2O to ppm K
N is given as N, so no conversion factor is needed.

An example: Bloom is 5% stated P, and say you want 50 ppm final P in your nutrient solution.
So do you mix it 1 to 1000? (5% is 1000x 50 ppm) No. the stated 5% are calculated as P2O5. You'd end up with 43.6% x 50 ppm = 21.8 ppm. To arrive at the desired 50 ppm youneed to use 2.29 times as much. (1 divided by .436 is about 2.29)
cn

plast00 said:

sorry but can someone break this down a little for me? i just dont quite understand the whole concept

Click to expand...

Me to i still dnt understand

I believe he wants to do Lucas Formula. Yes, Lucas formula is 1 part micro, 2 parts bloom, which gives 5-10-9