Matching Drivers and COBs

Can someone confirm that i figured this properly before i order please. Will 3 vero 29 v2 4000k and 1 vero 18 4000k @1400ma on a hlg-185-c1400b work properly? I am getting 142v total with the spreadsheet info for the cobs. The PDF says 71v-143v for the driver. That is cutting it close. Does anyone else run this setup? Thank you.:joint:
 
Red, you do have some headroom to at least 160v before the driver will shut down, it is listed in overvoltage
protection. From my understanding it will reduce the amps out slightly so it does not exceed the 200 watt rating.
Try asking the vero guys for a definitive answer. OG
 
OldGrower said:
approx 90 watts per chip 90x6=540 watts
Click to expand...
If the driver is at 600W how will I reduce the cobs to 540? id like to get a high proton efficiency too. Can I run 8 cobs off 600H-42B? I might have to go with the 320H and use 4 cobs. Ive really been trying to reduce my cost and get the most efficiency in photons as well, but be able to drive the cobs hard enough to justify paying for them.
 
Im trying to figure out how to calculate how many amps I can put on my 20 amp circuits so I can know many I can plug in
 
OldGrower said:
Red, you do have some headroom to at least 160v before the driver will shut down, it is listed in overvoltage
protection. From my understanding it will reduce the amps out slightly so it does not exceed the 200 watt rating.
Try asking the vero guys for a definitive answer. OG
Click to expand...
Right on OG. Thank you for taking the time to answer man. Good luck to you also!:joint:
 
will hlg-600h-36a @2.78A drive cxb3070 BB if they are supercooled? and how many
its not listed at that amperage


if I plug the 3070 into cree's calculator the chart goes up to 2.8A

since my cooling apparatus has probably thousands of watts of heat displacement..
 
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I wish I could get just a frickin inkling about this topic. I've read the entire thread twice and only feel more clueless. :cry:
 
is running 2 hlg-240h-c1400 in parrallel going to be too much for my cree cxb3070 with watercoolong or and I going to have to go with the c1050

if I do go with the 1050 can someone tell me the output?
 
giantsfan24 said:
I wish I could get just a frickin inkling about this topic. I've read the entire thread twice and only feel more clueless. :cry:
Click to expand...
Have you watched Growmau5’s videos on his youtube channel? For me it finally started to gell (sizing drivers to cobs and that the forward voltage varies depending on how hard they are driven) after watching the videos several times. :mrgreen:
 
BuddyColas said:
Have you watched Growmau5’s videos on his youtube channel? For me it finally started to gell (sizing drivers to cobs and that the forward voltage varies depending on how hard they are driven) after watching the videos several times. :mrgreen:
Click to expand...

Yes I have but I think going over it another 100 x might be best. Fortunately, these guys have been awesome enough to piece it together really well for us that I can build a nice cost efficient light that will work.

I'm doing a lot of reading and will get it eventually albeit never as good as supra, greengenes or growmau but at least well enough to grow when it's legal. :-)
 
Djloud said:
Whats everyones thoughts about the meanwell hlg 240h-36a
Click to expand...

Here are the specs.

http://www.meanwell.com/mw_search/hlg-240h/HLG-240H-SPEC.PDF

I'm just learning this stuff and If I understand the calculations correctly (please school me if I'm wrong ;)) the voltage range is 127 ~ 431VDC and figuring the cob dcv is 36v that would mean you can up to 12 cobs (431VDC divided by 36V = 11.97222.

I think this is where the amperage thing comes into play. The rated current is 6.7A and if I've got this right the you take the amps and divided by number of cobs ( 6.7 divided by 12 cobs = 0.55) so the cobs would be very efficient but running pretty soft. If your were to run 6 cobs @ 36v the amps per cob would be 1.116.

Well guys, did I get the math right?
 
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speyfly said:
Here are the specs.

http://www.meanwell.com/mw_search/hlg-240h/HLG-240H-SPEC.PDF

I'm just learning this stuff and If I understand the calculations correctly (please school me if I'm wrong ;)) the voltage range is 127 ~ 431VDC and figuring the cob dcv is 36v that would mean you can up to 12 cobs (431VDC divided by 36V = 11.97222.

I think this is where the amperage thing comes into play. The rated current is 6.7A and if I've got this right the you take the amps and divided by number of cobs ( 6.7 divided by 12 cobs = 0.55) so the cobs would be very efficient but running pretty soft. If your were to run 6 cobs @ 36v the amps per cob would be 1.116.

Well guys, did I get the math right?
Click to expand...
I too am a newbie...someone correct me if Im wrong, but to maximize this driver one would have to run in parallel (some do not care to run cobs in parallel).

I think the voltage range you are referring to is input (it can take 120v or 240v VAC for instance)...

In series, you would have to run it @ 3.3 - 3.6A (6.7 would blow even a 3590)...

In series, @ 3.3A x 36V = 118.8 W, you could only run (2) cobs for total of 237.6W...

It seems to me, one would have to run in parallel...one could run (9) cobs @ .7A for example...

This is likely why peeps choose 240h 700 (and the like)...can run in series and dont have to mess w added safety precautions that you do in parallel...

Edit: I suppose, as you pointed out, if someone were to overcome the pitfalls of parallel wiring cobs...theoretically, one could obtain crazy levels of efficiency and drive large number of cobs w one driver (Ex: (20) 3590 cobs @ .335A )
 
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