tags420
Well-Known Member
The math you did is not how either of the equations you showed are expressed would be done. But the math you did makes that .0083593 figure make sense and how used. Just not sure how you got there. But whatever...I have to do it in two steps but I still get the right answer. I like that all in one though...just the fact that I cant get it soved down to that point myself is bothering me.For the basic equation we're using to get watts to uMoles run the 630 x 1.5 (watts not mW) x .0083593 = 7.89 radiated uMole/s. Now add the rest of your 610-700nm wavelengths in and you'll have your (F) region values.
[FONT=&]Photon[SUB]µMol[/SUB] Power(λ = 119.62657/λ[SUB]nm[/SUB] Watts/µMol[/FONT]/s
What all of this has shown me is that I've got to give an explanation that includes a SDG and a how this is plotted on a nm x nm basis. My next update will include that.
Even with the official equations used posted, my brain hurts. I need a break and a bowl.
I sent the link to apache. I wonder what their thoughts on whole VCF system will be.