Here is the schematic drawing for how I wired the LEDs as asked. Its not rocket science and anyone who has some electrons background already knows this. I am posting this so that maybe I can inspire someone to get into this.
As you see the groups of different color LEDs, I just grouped them together. So lets say you look at the red group of 5 LEDs, well if you wanted to add another 5, you connect them the same way as above. You can use as much LEDs as your power supply can handle.
For now, I got some cheap AC to DC converters off ebay. If you go here:
https://www.rollitup.org/do-yourself/208286-diy-cheap-led-array.html This is where I made my LED array version 1. I am doing my version two. As for the converters (power supply), I had modified them. They were origionally made for car adaptors, but I dismantaled it and added some wires.
As for a power supply, theres a cheap way to make one. If you have an old power supply (PSU) from an old computer, you can modify it to power your LEDs. I found this site very helpful:
http://www.magicratproductions.com/magicforum/viewtopic.php?f=5&t=131
I will be making one myself to power my LEDs. The benifit with these power supplies is that it will have high current capacity.
My current power supplys are 1A. There is two of them. If your LEDs are suposed to draw about 20 mA of current, idealy you will need about 50 groups of LEDs (those 5 red LEDs after the resistor is what I call a group.)
With a cheap power supply, depending on the specs, you can run anywhere from 600 to over 1000 led groups. If its all red, thats about 3000 - 5000 LEDs.
I also used a 12v DC power supply. You can use a 24, and have 10 leds in one group instead of 5 with one resistor.
Something to keep in mind is this formula: Voltage(V) = Current (I) x Resistance (R)
Lets say I have a red LED. It drops about 1.8v to 2.2v (check your specs sheet). This means that if I have 1 LED and 1 Resistor, My LED will have about 2.2v across it, and the resistor will have 9.8v across it.
With that being said, we know the voltage across the resistor, and we know what is the optimal current for the LED (20 mA ... the little m means that it is 0.02 A, if you are not familiar with engineering notation)
Now we can find out what resistor we can use. 9.8v = (0.02)R
R = 490 ohms. So we look for a 490 ohm resistor.
Now we look for a resistor with that value. Radio shack and Ebay sell these. The resistors will have color bands on them to indicate their value. Here is a website to decode the color bands:
http://www.dannyg.com/examples/res2/resistor.htm
When buying resistors for the project, I used 1/4 watt resistors.
With that being said, we can optimize to have the maximum number of LEDs in series (in a row connected positive to negative leads). We know that the red ones drop about 1.8 to 2.2v. If we use 6, the maximum that our LEDs will drop is 13.2v. Our power supply cant handle that. If we connect 6 or more LEDs, they wont turn on. It will be like an open circuit.
If we use 5, we will be dropping 11v. This will leave 1v across our resistor. With the formula above, you can calculate which resistor you need.
V = 1V
I = 20mA or 0.02A
R = ?
If you look at my DIY array thread, you will see in real how I wired them. Soldering is key, and with my Version 2 array, I hot glued the LEDs together.
It is pretty simple and anyone can do it. LEDs are cheap. My plant is only a few weaks old but it looks like it has more then enough light.
The heat produced by the LEDs is about 40c. When I touch it, its no warmer then my body. They are on all day and that is all the heat that they produce.
I will connect a wattage measurement tool (kill-a-watt) thing to see how much wattage im drawing.
I will post the wiring for my PSU driver for my LEDs, and my completed LED array V2. Its going to be huge.
Also, theres an error in the picture that I just realized. The LEDs above the red should say amber.