CobKits
Well-Known Member
so lets be all caveman and take a 1/4" piece of solid aluminum bar which should be cheaper than a heatsink
if you had a 1 square foot piece of this, is it safe to assume that you radiate heat from top and bottom and so you count 2 square feet of surface area (negating edge thickness)
1 sq ft = 930 cm^2
2 sq ft = 1860 cm^2
used passively thats 1860/120 = 15.5 heat watts that can be dissipated
with fans blowing on both sides thats 1860/40 = 46.5 W
amirite? or do we only count the top (im thinking passive... on a large sheet where the heat could get 'trapped' underneath)
if you had a 1 square foot piece of this, is it safe to assume that you radiate heat from top and bottom and so you count 2 square feet of surface area (negating edge thickness)
1 sq ft = 930 cm^2
2 sq ft = 1860 cm^2
used passively thats 1860/120 = 15.5 heat watts that can be dissipated
with fans blowing on both sides thats 1860/40 = 46.5 W
amirite? or do we only count the top (im thinking passive... on a large sheet where the heat could get 'trapped' underneath)