Randomblame
Well-Known Member
I've just read the datasheet and I'm kind of confused in reading correctly this diagram:
View attachment 4058174
so, does this tell us that if, 1400ma, 20.5V are given, get a 200% Luminous Flux, so a 100% more, so double the flux at 700ma, 19.5V ? That would be a huge gain in lumens, double? am I right? cheers.
Would there be any cons?
Some math, don't know if I'm correct, few days in this led world and volt and amps etc etc.. so pardon me
1.4A x 20,5V = 28,7W double the lumens would be 2390 x 2 = 4780lm
4780lm / 28,7W = 166,5 lm/W so efficency drops but cost is great, for 7-8$ is a great price.
Can this be a good estimacy?
1. Yepp, LED's works this way.
2. You need better cooling at max. current. At least an aluminum C-channel while at nominal current no heatsink is required.
3. As I said in my post above, most users here drive the 2 and 4ft. strips at 1050mA or 150%.