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Low loss means?

Could you please inform yourself about choosing the right driver? You need to understand serial and parallel wiring plus how to read the datasheets from the LEDs and the driver. 1000 threads on here and google/youtube will help you as well.

Happy wife, happy life :D.

Oh jesus. Where have you been the past years? 510-610 nm drives photosynthesis very strong. Please inform yourself. This is an old myth/misunderstanding because the absoption peaks of chlorophyll where measure with isolated chlorophyll "molecules".... I recommend this paper...

You all should start measure the voltage over one LED, calculate the current and then check with the simulator which voltage bin this is. The voltage bin is just as important as the flux bin...

Wow, what scientific answer. Thanks for that valuable contribution to this topic. You don't have many friends, do you?

Do you have any source for that? Would appreciate a link.

Huge chip - i think it is a LM561C.

You lucky bastard! :D

Woaaaaarrr impressive piece of copper! Where have you got this and what was its purpose/where is it from? Please don't tell me you really want to waste this as an heatsink (in this form)! :D

umol/J chip level?

Oh man, having him on ignore is so joyful. Now I just get the funny parts. Great!

Dude, I compared the radiant efficiency of the china COB with the radiant efficiency of an LM561C. Plus I gave an example of how such a low radiant efficiency would affect the luminous efficiency of the LM561C. Equivalency at its best.

Are you familiar with the term LER and how you calculate it? Check out @alesh thread "The math behind". Its gold. LER (Luminous efficacy of radiation, I googled it because now im afraid of using the wrong eff... again :D) tells me, how many lumens a specific spectrum makes from 1 W radiation...

:D Okay okay, I mixed the words up. Efficacy is wrong, efficiency is what i meant. But please read the original post (and check the source, there is written that the COB was tested with 35V*1A). The test sheet says Strahlungsleistung, which is radiant power = 9,149 W. Radiant Power divided...

The question is: What do you think about an COB with an efficacy of mind-blowing 26 % ? Only an idiot would use it right? And what do you think about someone who wants to sell these COBs and tell his customers that these are fine COBs? Probably that he's a dick because he sells garbage to people...

That's just an example, I was trying to giving people an idea what 26 % efficacy means.... efficacy of an LM561C: 195 lm/W / 330 lm/W = 0,59 = 59 % efficacy. 86 lm/W / 330 lm/W = 0,26 = 26 % efficacy... only a brain dead monkey would use or sell them NOWADAYS. mahiluana, why don't you just...

This is from a test of a 50 W chinese grow COB powered with 35 V x 1 A = 35 W Strahlungsleistung = radiant power = 9,149 W That means: 9,149 W / 35 W = 0,2614 = fucking 26 % efficacy. For a comparison: With the typical 3000K CRI80 spectrum (LER = 330 lm), the LED would deliver 86 lm/W. Its a...

CRI70 all the way babe! We just need photons.